Question

the sum of three consecutive positive integer is 39. find these integer

Answer 1

Heya.....!!!!

HERE IS YOUR ANSWER

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Let the three consecutive positive integers be 'X', 'x+1', 'x+2'.

As per question,
x+x+1+x+2 = 39
3x+3 = 39
3x = 39-3
3x = 36
x = 12

So integers are :
x = 12
x +1 = 12+1 = 13
x +2 = 12+2 = 14

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HOPE IT HELPS!!!!

Answer 2

Let the first number = x
Then the other two consecutive numbers will be (x+1) and(x+2)
Now sum of these three consecutive numbers = 39
x + (x+1) +(x+2) = 39
x + x + x +1 +2 = 39
3x + 3 = 39
3x = 39-3
3x = 36
x = 36/3

x = 12
the other two numbers are
x+1 = 13
x+2 = 14
Checking
12+13+14 = 39