The sum of three consecutive positive integer is 39 find these integers
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Answered by
3
Heya !!!
Let three consecutive positive integer's are X , X + 1 and X + 2.
According to question,
X + X + 1 + X + 2 = 39
3X + 3 = 39
3X = 39-3
X = 36/3 = 12
First integer = X = 12
Second integer = X + 1 = 12 + 1 = 13
And,
Third integer = X + 2 = 12 + 2 = 14.
★ HOPE IT WILL HELP YOU ★
Let three consecutive positive integer's are X , X + 1 and X + 2.
According to question,
X + X + 1 + X + 2 = 39
3X + 3 = 39
3X = 39-3
X = 36/3 = 12
First integer = X = 12
Second integer = X + 1 = 12 + 1 = 13
And,
Third integer = X + 2 = 12 + 2 = 14.
★ HOPE IT WILL HELP YOU ★
Answered by
1
Let the three numbers be: x-1, x and x+1.
-Therefore, x-1 + x + x+1 =3x = 39
-Hence x, the middle number is 13.
-The other two numbers are 12 and 14.
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