Question

the sum of three consecutive positive integers 432. find the numbers​

Answer 1

answer of your question

Answer 2

Answer:

Let the three consecutive positive integers be x , x+1 and x+2

now,

= x + x+2 + x+3 = 432

= 3x + 3 = 432

= 3x = 432 - 3

= 3x = 429

x = 429/3

x = 143

now the three consecutive positive integers are:-

x = 143

x+1 = 143 + 1 = 144

x + 2 = 143 + 2 = 145

143 + 144 + 145 = 432

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