Question

the sum of three consecutive positive integers is 207 find the number​

Answer 1

Answer:

68 , 69 and 70

Step-by-step explanation:

let one no. be x

then , x + (x + 1) + (x + 2) = 207

3x + 3 = 207

3x = 207 -3 = 204

x = 204 / 3

x = 68

x+1 = 69

x+2 = 70

Hpe it will help u

Answer 2

Answer:

68,69 and 70.

Step-by-step explanation:

As per the provided information in the given question, we have :

• Sum of three consecutive positive integers = 207

We are asked to calculate,

• The numbers

Firstly, let's us understand what is meant by consecutive numbers. Consecutive numbers are the numbers that form a series, which've a common difference.

Let us assume the three consecutive positive numbers as x, (x + 1) and (x + 2).

Now, according to the question the the sum of three consecutive positive integers is 207. Writing it in the form of an equation,

$\longmapsto \rm { x + (x + 1) + (x + 2) = 207}$

Removing the brackets.

$\longmapsto \rm { x + x + 1 + x + 2= 207}$

Grouping all the like terms.

$\longmapsto \rm { x + x + x + 1 + 2= 207}$

Performing addition of the like terms.

$\longmapsto \rm { 3x + 3 = 207}$

Transposing 3 form L.H.S to R.H.S, changing its sign.

$\longmapsto \rm { 3x= 207- 3}$

Performing subtraction in R.H.S.

$\longmapsto \rm { 3x= 204}$

Transposing 3 from L.H.S to R.H.S.

$\longmapsto \rm { x= \cancel{\dfrac{204}{3}}}$

$\longmapsto \rm { x= 68 }$

Now, as we have assumed as the three consecutive positive integers as x, (x + 1) and (x + 2). so, now substituting the values of x in their algebraic expressions to find those numbers.

First Number :

$\longmapsto \bf { x= 68 }$

Second Number :

$\longmapsto \rm { (x+ 1)}$

$\longmapsto \rm { (68+ 1)}$

$\longmapsto \bf { 69}$

Third number :

$\longmapsto \rm { (x+ 2)}$

$\longmapsto \rm { (68+ 2)}$

$\longmapsto \bf {70}$

∴ The numbers are 68,69 and 70.