The sum of three consecutive positive integers is 39.find these integers.
Answers
Answered by
0
Answer:
Step-by-step explanation:
Let the three consecutive positive integers are x, (x + 1) and (x + 2 ).
According to the question,
Sum of the three consecutive positive integeintegers = 39
∴ x + x + 1 + x + 2 = 39
⇒ 3x + 3 = 39
⇒ 3x = 39 - 3
⇒ 3x = 36
⇒ x = 36 / 3
⇒ x = 12
∴ The three consecutive positive integeintegers
= x, x+ 1 and x + 2
= 12 , 12 + 1 and 12+ 2
= 12, 13 and 14 is the answer.
Answered by
1
Answer:
12, 13, 14
Step-by-step explanation:
Let the unknown values be x, x+1, x+2.
Then,
x+(x+1)+(x+2)=39
= 3x+1+2=39
= 3x=39-3=36
= x=36÷3=12
x=12
x+1=13
x+2=14
12+13+14=39
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