The sum of three consecutive prime numbers is 41. What will be the lowest
number in them?
(A) 11
(B) 9
(C) 19
(D) 15
famousdiwakar:
11+13+17=41 therefore answer is 11
Answers
Answered by
3
Answer:
prime number <= 41 are:
1, 3, 5, 7, 11, 13, 17, 19, 23, 29, 37, 41
The only consecutive prime numbers forming the sum 41 are:
11 + 13 + 17
the smallest number is 11.
Step-by-step explanation:
thanku
can i ask you one question
Answered by
1
D is the correct answer
Because 15 +16+17=
Because 15 +16+17=
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