Question

The sum of three consecutive prime numbers is 83. What shall be the square of the largest amongst the three numbers if its digits are reversed?

Answer 1

Given: the sum of three consecutive prime numbers is 83.

To find: what shall be the square of the largest amongst the three numbers if its digits are reversed?

explanation:

As we know that,

The three consecutive prime numbers whose sum is 83 are,

                                  = 23,29,31

Now the largest number among them is = 31

And,

if we reverse the digits of 31 then it will be = 13

the square of 13,

                                  $13^{2} = 169$

Hence 169 will be the square of the largest amongst the three numbers if its digits are reversed.

Answer 2

Given,

The sum of three consecutive prime numbers = 83

To find,

The square of the largest amongst the three numbers if its digits are reversed

Solution,

We can solve this problem like the following method

If the three consecutive prime numbers whose sum =83

Therefore,

The numbers will be 23, 29, 31.

The largest number among them is 31.

And,

if we reverse the digits of 31 then it will be 13.

13²= 169

i.e., the square of 13 is 169.

Thus, 169 will be the square of the largest amongst the three numbers if its digits are reversed.