The sum of three consecutive term of an AP is 30 and their product is 360 find the term
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(a+b) (a) (a-b)=30
3a=30
a=10-----(1)
(a+b) (a-b) (a)=360
(a^2-b^2)(a)=360
3^2-b^2×3=360
b^2=360-27
b^2,=
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Answer:
refer this notes ok and do well
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