Question

The sum of three consecutive term of an ap is 36 find their products 1140 consider term in descending order

Answer 1

Step-by-step explanation:

let the middle term be a

difference be x

first term = a-x

second term= a

third term = a+x

sum of term= 36

a-x+a+a+x=36

3a= 36

a=12

product of term = 1140

(a-x)a(a+x)=1140

(12-x)(12+x)12=1140

(12-x)(12+x)=95

12²-x²=95

144-x²=95

144-95=x²

49=x²

7=x

first term = a-x=12-7=5

second term= a= 12

third term = a+x= 12+7=19

19>12>5

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