Question

the sum of three consecutive terms in an ap is 6 and their product is-120. find the three numbers​

Answer 1

Answer:

-6, 2,10

hope it helps...

Answer 2

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GIVEN :

The sum of three terms of an AP = 6

The product of them = - 120.

TO FIND :

The terms.

SOLUTION:

Let the three terms be (a - d) , (a ), (a + d ).

Where a is the first term of an AP

d is the common difference of an AP.

=> a - d + a + a + d = 6

3a = 6

a = 6/3

a = 2

=> ( a - d) × ( a ) × ( a + d ) = - 120

a^3 - a (d^2) = - 120

(2) ^3 - 2( d^2) = - 120

8 + 120 = 2 (d^2)

128 = 2 (d^2)

64 = d^2

d = 8

The three terms are ,

=> 2 - 8 , 2 , 2 + 8

=> -6 , 2 , 10

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