Question

The sum of three consecutive terms in an AP is 6 and their product is -120.Find the three numbers.​

Answer 1

Answer:

Let the number be a-d, a, a+d

Sum=3a=6

a=2

Product =a(a^2 - d^2) =-120

2(4-d^2) =-120

d^2 - 4=60

d^2 =64

d=-8,8

Therefore the numbers are - 6,2,10