the sum of three consecutive terms in ap is 6 and their product is -90. Find the terms
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Given : sum of three consecutive terms in ap is 6 and their product is -90.
To find : the terms
Solution:
Let say three numbers are
a - d , a , a + d
Sum = a-d + a + a + d = 6
=> 3a = 6
=> a = 2
numbers are
2-d , 2 , 2 + d
Product = (2 - d)(2)(2 + d) = - 90
=> 4 - d ² = -45
=> d² = 49
=> d = ± 7
2 - 7 , 2 , 2 + 7 = -5 , 2 , 9
or
2 -(-7) , 2 + (-7) = 9 , 2 - 5
Three terms are
-5 , 2 & 9
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