Question

the sum of three consecutive terms in ap is 6 their product is -120 find three numbers

Answer 1

the three consecutive numbers is 20,21,22

Answer 2

solutions:-

Let the three terms be
 a-d,a,a+d  
sum=a-d+a+a+d=6
     =3a=6
     a=2


 product =(a-d)a(a+d)=-120
            (a^2-d^2)a=-120
            (4-d^2)2=-120
             8-2d^2=-120
             -2d^2=-128
            d^2=64
                d=8


ap are -6,2 10