Question

The sum of three consecutive terms of an A.P is 21 and their product is 336 find the numbers.

Answer 1

Answer:

numbers are 6,7,8

Step-by-step explanation:

let the numbers be a-d, a, a+d

sum is 21

a-d+a+a+d=21

3a=21

a=7

product is 336

(a-d)(a+d)a= 336

putting value of a in above equation

7²-d²=336/7

49-d²= 48

-d²=-1

d=1

first number,a-d=6

second number,a=7

third number,a+d=8