Question

The sum of three consecutive terms of an A.P is 36 and their product is 1140. Find
the terms.
[ consider the terms to be in descending order]
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Answer 1

Your answer is in attachment .

Answer 2

Answer:

5,12,19

Step-by-step explanation:

suppose, one of the numbers is a

another is a+d and another is a-d

Now, a-d+a+a+d = 36

or, 3a = 36

or, a = 12

again, a*(a+d)*(a-d) = 1140

or, a^2-d^2 = 1140/12 = 95

or, 12^2 - 95 = d^2

or, d^2 = 49

so, d = 7

Now, a - d = 12 - 7 = 5

and a + d = 12 + 7 = 19

thus the numbers are, 5, 12, 19