Question

The sum of three consecutive terms of an AP.
30 and their product is 360Find the terms.​

Answer 1

Answer:

Let the three consecutive terms be n,(n+1),(n+2)

the sum of the three consecutive terms is 30

n+n+1+n+2=30

3n+3=30

3n=30-3

3n=27

n=9

substitute n=9

n+1=9+1=10

n+2=9+2=11

hence,the three terms are 9,10 and 11.

Thanks

Answer 2

This is your answer in the image

In hope that you will get it.......