"The sum of three consecutive terms of an AP is 21 and the sum of the squares of these terms is 165. "Find these terms
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Step-by-step explanation:
a+d+a-d+a=21
3a=21
a=7
(a+d)^2+a^2+(a-d)^2=165
on solving, we get
3a^2+2d^2=165
147+2d^2=165 putting a value from above
2d^2=18
d^2=9
d=3
terms are:- a-d =4
a=7
a+d=10
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