Question

the sum of three consecutive terms of an ap is 24 the ratio of the second and sixth term is 1 is to 2 find the 25th term​

Answer 1

Answer:

Sn=n/2(2a+(n-1)d)

24=3/2(2a+(3-1)1)

we get a=7

then by formula Tn=a+(n-1)d apply krke t25 nikal lena h