the sum of three consecutive terms of an ap is 3 and thier product is -35. find the numbers
Answers
Answered by
7
Answer:
Step-by-step explanation:
By solving with the help of the equation
Sn=n/2(a+l)
We get n=10
Puting the value in
Tn=a+(n-1)d
By solving this equation
We get d=3
HOPE THIS WILL HELP U
AkshithaZayn:
explain it please
Answered by
86
Hey!
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★Arithmetic Progressions ★
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=> Let the three consecutive terms be ( a - d ) , a and ( a + d )
➡According to the Question ,
• There Sum is 3 so we will add the terms of A.P
=> a + a + d + a - d = 3
=> 3a = 3
=> a = 1 ✔
•°• The terms become ( 1 - d ) , 1 and ( 1 + d)
•their product is -35 . So multiply the terms.
=> 1 ( 1 + d ) ( 1 - d ) = -35
=> 1 - d² = -35
=> d² = 36
=> d = +- 6 ✔
Now we shall take both negative as well as positive value of d.
1. When d = 6
★The terms of the AP are -5 , 1 and 7 !
2. When d = -6
★The terms of the A.P are 7 , 1 and -5 !
___________________________________________________________
____
_____________________________________________________________
★Arithmetic Progressions ★
_____________________________________________________________
=> Let the three consecutive terms be ( a - d ) , a and ( a + d )
➡According to the Question ,
• There Sum is 3 so we will add the terms of A.P
=> a + a + d + a - d = 3
=> 3a = 3
=> a = 1 ✔
•°• The terms become ( 1 - d ) , 1 and ( 1 + d)
•their product is -35 . So multiply the terms.
=> 1 ( 1 + d ) ( 1 - d ) = -35
=> 1 - d² = -35
=> d² = 36
=> d = +- 6 ✔
Now we shall take both negative as well as positive value of d.
1. When d = 6
★The terms of the AP are -5 , 1 and 7 !
2. When d = -6
★The terms of the A.P are 7 , 1 and -5 !
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