Question

the sum of three consecutive terms of an ap is 30 and their product is 360 find the terms

Answer 1

let the 3 terms be a-d, a and a+d

a-d+a+a+d=30

=a=10

(a-d)(a)(a+d)=360

=(10-d)(10+d) = 360/10 = 30

= 100 - d² =36 (identity)

= d² = 64

= d= (plus minus) 8

numbers= 2,10,18 OR 18,10,2

Answer 2

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