The sum of three consecutive terms of an Arithmetic progression is 12 and their product is 48. Find the all terms of progression
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Answer:
let terms be (a-d),a,(a+d)
sum =12
a-d+a+a+d=12
3a=12
a=4
product
48 =(a-d)(a)(a+d)
put the value of a to get value of d
and u will get ur answer
plz mark brainliest
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