Question

The sum of three consecutive terms of an Arithmetic progression is 12 and their product is 48. Find the all terms of progression

Answer 1

Answer:

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Answer 2

Answer:

let terms be (a-d),a,(a+d)

sum =12

a-d+a+a+d=12

3a=12

a=4

product

48 =(a-d)(a)(a+d)

put the value of a to get value of d

and u will get ur answer

plz mark brainliest