Question

The sum of three consecutive terms of an arithmetic progression is -3 and their product is 15. find the terms


please help!!!

Answer 1

Step-by-step explanation:

let terms of AP : (a-d),(a),(a+d)

=sum of these terms are 3a

=3a = -3

a = -1

a²-d²(-1) = 15

-1-d²=15

d² = 15 +1

d =√16

d = ±4

thus the terms are:

3, -1,-5

or

-5, -1, 3

Answer 2

Answer:

let three consecutive terms = a, a-d, a+d

a+a+d+a-d= -3

3a=-3

a=-1

a×(a+d)×(a-d)=15

-1×-1+d×-1-d=15

-1(1-d sq)=15

1-d sq =-15

1+15=d sq

16=d sq

d=4

terms= -1, 3 , -5

= -5,-1,3