The sum of three consecutive terms of an
increasing A.P. is 51. If the product of the first
and third of these terms be 273, then third term is.
(A) 13 (B) 17 (C)21 (D) 9
plz give answer with method
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Answered by
4
3 consecutive no.=x-a,x and x+a
Given, x-a+x+x+a=51
3x=51 so x=17
Also, Given that product of 1st and 3rd no. is 273
I.e.(x-a)(x+a)=273
x²-a²=273
put x=17 we get,
a²=17²-273=289-273
a²=16
so a=4
so 3rd no.=x+a=17+4
=21.
vibhadudile60:
thank you very much
Answered by
3
Answer:
Let 1st term be a-d
2nd term a
3rd term a+d
Sum is 51
a-d + a +a+d =51
3a =51
a=17
Product of 1st & 3rd =273
a-d*a+d=273
17-d*17+d=273
289-d square=273
d square=16
d =4
Then 3rd term is a+d
17+4=21
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