Question

The sum of three consecutive terms of an increasing ap is 51 and the product of first and third term of these terms is 273 find the third term

Answer 1

Answer:

Given :

sum of three consecutive terms in an increasing AP=51

let the three terms be (a+d); (a);(a- d)

a+d+a+a- d=51

3a=51

a=17

and also given that , product of first and third terms =273

(a+d)(a- d)=273

a²-d²=273

(17)²-d²=273

289-d²=273

289-273=d²

d²=16

d=√16

d=4

Third term=(a-d)=17-4=13.