Question

the sum of three consecutive terms of AP is 48 and the product of first and last is 252 then d=?

Answer 1

Answer:

Step-by-step explanation:

Hey !! It's simple

Let three consecutive terms of an AP be ( A - D ) , A and ( A + D ).

According to the question

Sum of three consecutive terms = 48

A - D + A + A + D = 48

3A = 48

A = (48/3) = 16.

First term ( A ) = 16.

Again,

Product of first term and last term = 252

( A - D ) × ( A + D ) = 252

( A)² - ( D)² = 252

(16)² - ( D )² = 252

(D)² = 256 - 252

D² = 4

D = ✓4 = 2

Hence,

Common difference ( D ) = 2.

Answer 2

Answer:

answer for this is ,+-2