The sum of three consecutive terms that are in AP is 27 and their product is 288.find the AP
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Let the number be a - d , a , a + d .
GIVEN that
- a - d + a + a + d = 27
- (a - d) × a × (a + d) = 288
Solving First eqn. , we get
- 3a = 27
- a = 9
Putting value of a = 9 in second eqn. we get
- (9 - d) × 9 × (9 + d) = 288
- (9)² - (d)² = 32
- d² = 81 - 32
- d² = 49
- d = ±7
THREE TERMS ARE
- 2 , 9 , 16
- or
- 16 , 9 , 2
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