Question

the sum of three consecutive terms that are in AP is 27 and there product is 288 find the terms ​

Answer 1

Therefore three consecutive terms are: (9−7)=2,(9), and (9+7)=16. ( 9 − 7 ) = 2 , ( 9 ) , and ( 9 + 7 ) = 16. Hence the three consecutive terms are: 2,9, and 16 2 , 9 , and 16 .

Answer 2

Answer:

number is -12 , 9 , 30

Step-by-step explanation:

let the these three consecutive number is

(a - d),(a),(a + d)

therefore, sum of these three number is

(a-d) + (a) + (a + d) = 27

3a = 27

a = 27/3 = 9

product of these three number is

(a-d)*(a)*(a+d) = 288

(a^2 - d^2)*(a)  = 288

put the value of 'a'

(9^2 - d^2)9 = 288

(81 - d^2)9 = 288

729 - d^2 = 288

d^2 = 729 - 288

d = √441 = 21

therefore the number is

(a-d) = 9 - 21 = - 12

(a) = 9

(a+d) = 9 + 21 = 30