Question

The sum of three consecutivemultiples of 9 is 999 find these multiples

Answer 1

Answer:

324, 333, 342

Step-by-step explanation:

Let the nos be 9x, 9(x+1), and 9(x+2)

we know that the sum is 999. So,

9x + 9(x+1) + 9(x+2) = 999

9(x+x+1+x+2) = 999

3x+3 = 111

3(x+1) = 111

x+1 =`37

x = 36.

SO, nos are-

9x= 9*36= 324

9(x+1)= 9*37=333

9(x+2)= 9*38= 342

Answer 2

Answer:let a-9,a,a+9

Sum of a-9+a+a+9=3a =999

Therefore, a=333

Hence 324,333,342 are three required multiples

Step-by-step explanation: