The sum of three consequent even natural number is 48 find the greatest of these numbers
Answers
Answered by
6
Hey
Let, the smallest number be x
second number =x+2
third number =x+4
then A/Q
x+x+2+x+4=48
3x+6=48
3x=42
x=14
The greatest number =x+4=14+4=18
Hope it helps to you.
Let, the smallest number be x
second number =x+2
third number =x+4
then A/Q
x+x+2+x+4=48
3x+6=48
3x=42
x=14
The greatest number =x+4=14+4=18
Hope it helps to you.
Answered by
2
Hey Mate
your answer is ----
Let, the three consecutive number be
x , x+2 & x+4
therefore , by the given condition
x+x+2+x+4= 48
=> 3x+6 = 48
=> 3(x+2) = 48
=> x+2 = 16
=> x = 16 - 3
=> x = 14
so, the three consecutive number is 14,16,18
hence , greatest number is 18
===================
HOPE IT HELP YOU
===================
your answer is ----
Let, the three consecutive number be
x , x+2 & x+4
therefore , by the given condition
x+x+2+x+4= 48
=> 3x+6 = 48
=> 3(x+2) = 48
=> x+2 = 16
=> x = 16 - 3
=> x = 14
so, the three consecutive number is 14,16,18
hence , greatest number is 18
===================
HOPE IT HELP YOU
===================
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