the sum of three conseuctive multiples of 6 is 216.find the number
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x=216. Therefore, 1st multiple of 6 = 216. 2nd multiple of 6 = x+6=216+6=222. 3rd multiple of 6 = x+12=216+12=228.
Answered by
1
Answer:
x=216. Therefore, 1st multiple of 6 = 216. 2nd multiple of 6 = x+6=216+6=222. 3rd multiple of 6 = x+12=216+12=228.
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