Question

The sum of three consicative terms of an A.p.is 30 & their product is 60.Find the terms​

Answer 1

Answer:

(a-d)+(a)+(a-d)=30

a-d+a+a-d=30

3a=30

a=10

Step-by-step explanation:

Answer 2

Answer:

the sum of three consecutive

( a-d) +(a)+(a+d)=30

a-d+a+a+d=30

3a=30

a=10

(a-d)(a+d)=60

(10-d)(10+d)=60

100+10d-10d-d2=60

100-d2=60

100-60=d2

40=d2

d=6.32

a1=10

a2=a+d

a2=10+6.32

a2=16.32

a3=a+2d

a3=10+12.64

a3=22.64