the sum of three constructive natural number is 114 find the numbers
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sum of three consecutive natural numbers is 114
let the numbers be x,x+1,x+2
so, x+x+1+x+2=114
3x+3=114
3x=111
x=37
x+1=38
x+2=39
37+38+39=114
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Answer:
The three consecutive natural numbers are 37, 38, 39.
Step-by-step explanation:
First no. = x
Second no. = (x + 1)
Third no. = (x + 2)
According to the equation,
x + (x + 1) + (x + 2) = 114
= 3x + 1 + 2 = 114
= 3x + 3 = 114
= 3x = 114 - 3 = 111
Therefore, x = 111\3 = 37
Hence,
First no. = 37
Second no. = (37 + 1) = 38
Third no. = (37 + 2) = 39
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