Question

The sum of three digit numbers of a 2 digit number is 12 and the difference of the digits is 4 find the number if the tens digits is less than the ones digit

Answer 1

Answer:

Let the number = XYZ

So X+Y+Z=12

We can simplify this based on condition given

We will write

X =X

Y=X+2

Z=X-2

So X+Y+Z = X+X+2+X-2=12

3X= 12

X = 4

Hence Y =6

Z = 2

Number is 462

Easy…..