Question

the sum of three integers is 18 .the third integer is four times the second ,and the second integers is 6 more than the first find the integers?​

Answer 1

x+y+z= 18

z= 4y

y = 6+x

x+6+x +4(6+x) =18

6x = 18 - 6 - 24 =18- 30 = -12

x =-2

y= 4

z= 16