The sum of three integers is 228. The second integer is 1 more than the first, and the third integer is 2 more than the fist. Write an equation to determine the integers. Solve your equation.
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228=x+1x+2x
=4x=228
x= 228÷4
=57
1x=57×1
2x=57×2
=4x=228
x= 228÷4
=57
1x=57×1
2x=57×2
Answered by
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Let the three no.s be x, x+1,x+2
Given that,
total sum= 228.
therefore,
x+x+1+x+2= 228
3x+3=228
x= 75
(Equation is 3x-225= 0)
The no. are 75,76,77
Given that,
total sum= 228.
therefore,
x+x+1+x+2= 228
3x+3=228
x= 75
(Equation is 3x-225= 0)
The no. are 75,76,77
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