the sum of three no. in AP is 12 and sum of their cubes is 288. find the no.
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Answered by
6
hey.. here's ur solution !!
let the three no. in AP be a-d, a, a+ d.
3a = 12
a =4
also,
( 4-d)³ + 4³ + ( 4+ d) ³ = 288
= 64- 48d + 12d² - d³ +64 +64 + 48d +12d² + d³= 288
= 24 d² + 192 =288
d² = 4.
d = + or - 2
the numbers are 2, 4,6. or 6,4,2.
hope it might be helpful !!
let the three no. in AP be a-d, a, a+ d.
3a = 12
a =4
also,
( 4-d)³ + 4³ + ( 4+ d) ³ = 288
= 64- 48d + 12d² - d³ +64 +64 + 48d +12d² + d³= 288
= 24 d² + 192 =288
d² = 4.
d = + or - 2
the numbers are 2, 4,6. or 6,4,2.
hope it might be helpful !!
Answered by
2
Hello , here is Ur answer .....
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Hope it's helps u
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