the sum of three no.s in ap is 21 and their product is 231 find the numbers
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Let numbers in AP = (a-d),a,(a+d)
Sum=a-d+a+a+d=21
3a=21
a=7
(7-d)7(7+d)=231
49-d²=33
d²=16
d=4 or -4
Numbers are -1,3,7
Sum=a-d+a+a+d=21
3a=21
a=7
(7-d)7(7+d)=231
49-d²=33
d²=16
d=4 or -4
Numbers are -1,3,7
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