The sum of three no.s in AP is -3 and their product is 8 . Find the number s
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a+(a+d)+(a+2d)=-3
=>3a+3d=-3
=>a+d=-1=>a=-1-d
a.(a+d).(a+2d)=8
=>(-1-d)(-1-d+d)(-1-d+2d)=8
=>(-1-d)(-1)(-1+d)=8
=>(d+1)(d-1)=8
=>d^2-1^2=8
=>d^2=9
=>d=+3 or -3
a=-4 or +2
therefore the ap is
-4,-1,2 or 2,-1,-4
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