Question

The sum of three non-negative integers A, B and C is 24. Of these, two are equal and the other integer
is twice of either of them. What will be the maximum value of (AⓇB) + (BⓇC)?
(a) 128
(b) 196
(c) 169
(d) 144
​

Answer 1

Answer:

Option (d) = 144 is correct

Step-by-step explanation:

Given that the three non-negative integers are A, B and C

For the given conditions, we take

A = C ..... (1)

B = 2A = 2C ..... (2)

Also given that the sum of A, B and C is 24

i.e., A + B + C = 24 ..... (3)

Using (1) and (2), from (3), we get

C + 2C + C = 24

or, 4C = 24

or, C = 6

Then A = 6 and B = 12

Therefore (A × B) + (B × C)

= (6 × 12) + (12 × 6)

= 72 + 72 = 144 ,

which is the maximum value.