Question

The sum of three non-zero prime number is 100.one of them exceeds the other by 36. then the largest nimber is

Answer 1

let the three prime no. are 2, x and (x+36)


(here we have to take one no. is even because sum of three odd numbers can never be an even number i.e 100 and the only even prime no. is 2 so we have to take 2 as one of them)


now,
2+ x +(x+36) =100
2 +2x +36 =100
x = (100 -36-2)/2 =31

Hence, the no. are 2, 31 and 67
and the biggest among them is 67
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