Question

the sum of three number in 38 the ratio of the first number to the second number is 4 ratio 9 and the ratio of the second number to the third number is 9 and 16 the sum of the first and third number is​

Answer 1

Answer:

760/29   (According to your question)

Step-by-step explanation:

given, sum of 3 no.s = 38

          ratio of 1st to 2nd = 4:9

          ratio of 2nd to 3rd = 9:16

so, ratio of 1st:2nd:3rd = 4:9:16

let x be the proportionality constant.

so, the sum of 3 no.s,

ie., 4x+9x+16x = 38

=> 29x = 38

=> x = 38/29

=> the 1st number =  4(38/29) = 152/29

and 3rd number = 16(38/29) = 608/29

so, sum of 1st and 3rd = (152/29) + (608/29)

                                     = (152+608)/29

                                     = 760/29

verification:

2nd number = 9(38/29) = 342/29

so, sum of 3 no.s = (152/29) + (342/29) + (608/29)

                             = (152+342+608) /29                            

                             = 1102 /29

                             = 38

which is the given 1st condition.

hence verified.