The sum of three number in A.P. is 3 and their product is -35. find the number
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5,1,7 this is the answer or this question is wrongggg
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Answer:
The nos. are -5,1,7
Explanation:
Let the nos. be
(a-d),a,(a+d)
Sum=(a-d)+a+(a+d)=3
=>3a=3
a=1
product=(a-d)(a)(a+d)=-35
(a^2-ad)(a+d)=-35
a^3+a^2d-a^2d-ad^2=-35
a^3-ad^2=-35
Substituting a=1
1^3-1(d^2)=-35
-d^2=-35-1
-d^2=-36
d=6
Therefore, nos. are
(a-d)=1-6=-5
a=1
(a+d)=1+6=7
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