Question

The sum of three number is 132 .if the 1st no. be twice the 2nd and third number be one -third of the 1st then the 2nd no. is with solution

Answer 1

Let the 3 numbers be x, y & z

x = 2y
z = x/3
   = 2y/3

x + y + z = 132
2y + y + 2y/3= 132
3y + 2y/3 = 132
9y/3 + 2y/3 = 132
11y/3 = 132
11y = 132^3
       = 396
   y  = 396/11
       = 36

Therefore,
2nd no. = 36