Question

the sum of three number is 25 the second number is twice the first and third exceeds second 5 find the numbers​

Answer 1

Let the first number be x

so,

x+2x+2x+5 = 25

5x + 5 = 25

5x = 20

x = 20/5 = 4

The first number is x = 4

second number is 2x = 2*4 = 8

third number is 2x + 5 = 2*4 + 5 = 13

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Answer 2

Answer:

4,8, 13

Step-by-step explanation:

Take three numbers as x,y,z

x + y + z = 25  ---- (1)

A.C.Q,

y = 2x

x = y/2 ---- (2)

and

z = y + 5   ---- (3)

Place (2),(3) in (1).

y/2 + y + y + 5 = 25

=> y + 2y + 2y + 10 = 50

=> 5y + 10 = 50

=> y = 8

Place y = 8 in (2).

x = 4

Place y = 8 in (3)

z = 13

Hence, the numbers are 4,8 and 13.

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