Question

the sum of three number is 57 if twice the first number is 6 less than the second and the second number is 10 more than the third find the numbers​

Answer 1

Answer:

Let three number x, y, z

then we have given

x+y+z=57

and

twice of first number is 6 less then second no.

so,

2x+6=y

and second is 10 more then third

so,

y-10=z

from these equations

we come that..

put y and z in eq 1

x+2x+6+2x-4=57

5x+2=57

5x=55

x=11

and then 2x+6=y

22+6=y

y=28

z=y-10

z=28-10

z=18

it is your answer