the sum of three number is 57 if twice the first number is 6 less than the second and the second number is 10 more than the third find the numbers
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Answer:
Let three number x, y, z
then we have given
x+y+z=57
and
twice of first number is 6 less then second no.
so,
2x+6=y
and second is 10 more then third
so,
y-10=z
from these equations
we come that..
put y and z in eq 1
x+2x+6+2x-4=57
5x+2=57
5x=55
x=11
and then 2x+6=y
22+6=y
y=28
z=y-10
z=28-10
z=18
it is your answer
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