Question

the sum of three number is 57 if twice the first number is 6 less than the second and the second number is 10 more than the third find the numbers

Answer 1

consider the numbers x,y,z
X+y+z=57
2x=y-6
y=10+z
y=2x+6
z=y-10
=2x+6-10
z=2x-4
x+y+z=57
x+2x+6+2x-4=57
5x+2=57
5x=55
x=11
y=27
z=18

Answer 2

Answer:

x-11,y-27,z-18

Step-by-step explanation:

=x+y+z+=57

2x=y-6

y=2x+6

z=y-10

=2x+6-10

z=2x×4

x+2x+6+2x-4=57

5x+2=57

5x=55

x=11

y=27

z=18

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