Question

The sum of three number is 98. of the ratio between 1st and 2nd be 2:3 and that between 2nd and third be 5:8, then find the 2nd no.

Answer 1

a:b=2:3
b:c=5:8
=(5∗3/5:8∗3/5)
=3:24/5
a:b:c=2:3:24/5
=10:15:24
b=98∗15/49
=30

Answer 2

Answer:

Step-by-step explanation:

Let the three numbers be x, y and z.

Sum of the numbers is 98.

x + y + z = 98………………(i)

The ratio of the first to the second is 2/3.

x/y = 2/3.

x = 2/3 × y.

x = 2y/3.

The ratio of the second to the third is 5/8.

y/z = 5/8.

z/y = 8/5.

z = 8/5 × y.

z = 8y/5.

Put the value of x = 2y/3 and z = 8y/5 in (i).

2y/3 + y + 8y/5 = 98

49y/15 = 98.

49y = 98 × 15.

49y = 1470.

y = 1470/49.

y = 30 .

Therefore, the second number is 30.