Question

the sum of three number is an A.P. is 27 and their product is 405 .find the numbers

Answer 1

let a-d,a,a+d are three numbers in an A.P. then (a-d)+(a)+(a+d)=27 so 3a=27 means a=9 and (a-d)×(a)×(a+d)=405 so (a^2-d^2) ×a=405 then a^2-d^2=405/9 means a^2-d^2=45 then 81-d^2=45... d^2=81-45.......d^2=36 so d=6 hence the numbers are a-d= 3 and a=9 and a+d=15