the sum of three numbers 52. the third number is twice the second, and is also 2 less than 3 times the first. find the first number
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Let the three numbers be a, b and c.
Given:
- Sum of the three numbers is 52
- Third number is twice the second
- Third number is 2 less than thrice the first number
Solution:
Using the given conditions, we can write
- a + b + c = 52 ... (1)
- c = 2 b ... (2)
- c = 3 a - 2 ... (3)
From (2), we get b = c/2
From (3), we get a = (c + 2)/3
Substituting the values of a and b in (1), we get
- (c + 2)/3 + c/2 + c = 52
- ⇒ (2 c + 4 + 3 c + 6 c)/6 = 52
- ⇒ 11 c + 4 = 312
- ⇒ 11 c = 308
- ⇒ c = 28
Putting c = 28 in (2), we get b = 14
Putting c = 28 in (3), we get a = 10
Answer: The three numbers are 10, 14 and 28.
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