Question

The sum of three numbers in A.P. is 15 the sum of the squares of the extreme is 58.Find the numbers​

Answer 1

Step-by-step explanation:

Let the numbers be a-d,a,a+d

So sum of three numbers is 15.

a-d+a+a+d=15

3a=15

a=15/3=5

a=5

Sum of squares of extremes = 58

Therefore,

(a-d)^2 + (a+d)^2 = 58

a^2 + d^2 - 2ad + a^2 + d^2 + 2ad = 58

2(a^2 + d^2) = 58 [Dividing the whole expression by 2]

a^2 + d^2 = 29 [Substituting a=5]

5^2 + d^2 = 29

d^2 = 29 - 25 = 4

d = √4

d = ±2

If we take d = 2,numbers are:

a-d,a,a+d

= 5-2,5,5+2=3,5,7

If we take d=-2,numbers are:

5-(-2),5,5-2

=7,5,3

Numbers are 3,5,7 or 7,5,3

I hope it helps!

Answer 2

the answer is 3,5,7 hshdhdhjssjsjsjsjdhhdhdhdvsvzvzv zvzvzvzvzvxvxhx